Mole is known as the SI unit for measuring the amount of substance in any solution. Mole fraction is also referred to as a unit of concentration, which is equivalent to the number of moles of a component, which is divided by the total number of moles of a solution.
The mole fraction has no unit because it is a ratio. When added together, the mole fraction of all components in a solution will equal 1.
Thus, the Mole fraction, i.e., the ratio of a specific amount’s substance to the total moles of the solution, becomes one of the most common tools of equation balancing.
Example
you have a solution with 1-mole benzene, 2-moles of carbon tetrachloride, and a solution of acetone with 7-moles, where the mole fraction of the acetone is 0.7. you can determine this mole fraction by summing up the number of moles of acetone and then dividing by the total moles in the solution.
Moles of acetone =. 7moles
Add the total number of moles in the solution = benzene + carbon tetrachloride + acetone
= 1+ 2 + 7 = 10 moles as a total.
To determine the mole fraction of acetone divide, the number of moles of acetone by the total number of moles in the solution.
Mole fraction of acetone= Moles of acetone/ moles in the solution
= 7/10 = 0.7 mole fraction of acetone.
Since the mole fraction is required to calculate the number of moles involved in any reaction. So, you can use the Mole Ratio Calculator for calculating the value online.
Chemical Equation balance
A balanced equation typically involves the number of moles, atomic mass, and the total number of any reactant participating in any certain equation.
In case, if you are not able to achieve these numerical values, your equations are not meant to be well-balanced. So while doing any chemical reaction, one must know the ingredients and their quantities accurately to get prime results of balancing chemicals equations.
Example:
In an unbalanced equation, the reactant gives the products but cannot satisfy the conservation of mass.
Fe2O3 + C -> Fe +CO2
Above is an unbalanced equation, but we need the equation to be balanced for changes because both sides have neutral charges so that we maintain a state of equilibrium.
The reason behind this balancing of equations is to have the same number of each type of atom, component, or element on both sides of the arrow. The balanced equation is
2Fe2O3 + 3C -> 4Fe + 3CO2
So in the balanced equation of the chemical reaction, we have the total number of atoms, moles, and conservation of mass, which are the basic elements to calculate the theoretical yield of the chemical reaction. If you want to balance your equation without doing manual action, you can use Online Equation Balancer.
Role of Mole fraction in Chemical equation balance
Mole fraction plays the main supportive role in balancing the chemical equations in any reaction.
It will be easier for you to understand with the help of some examples by performing this chemical reaction below;
P4 + 5 O2 → P4O10
The above equation has one mole of phosphorus that reacts with five moles of oxygen, and the number of moles will react and make one mole of tetra-phosphorus dioxide.
Once you know the exact number of moles participating in a chemical equation, it’ll be easier to balance the equation.
The relation between the mole fraction and balance equation
Here we will discuss the methods of solving any chemical reaction while having a strong link with mole fraction. And this link is specified to build the conversion factors of balancing the chemical equations involved in the reactions. So then we can obtain the accuracy in our conversion factor.
As mentioned in the examples, it is obvious to understand the relation between the mole fraction and the balanced equation.
To determine the mole ratio, you just need a balanced equation. To balance any unbalanced equation, you need to know the number of elements or the components from the equation. And measure them in terms of grams or moles, which are the SI units of it.
Note: InfoDigitally is one of the best sites which is the platform for learning and making your concepts strong while studying digitally.
Author’s Bio:
I am a professional Chemist/Blogger & Content Writer. I have researched chemistry topics and help everyone learn Organic & Inorganic Chemistry and Biochemistry. Moreover, I loved to spend vacations on a Hill Station.
